Question

Which of the following atoms has the greatest number of unpaired electrons ?
V
Ti
Mn
Cr

Answer 1

Answer:

tin is the correct answer as it contains more electrons than others

Answer 2

Cr has the greatest number of unpaired electrons.

Explanation:

1. To find out which atom has the highest number of unpaired electrons, we have to see the electronic configuration of each atoms.

2. The electronic configuration of V which have atomic number 23 is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{2} {3d}^{3}$

Here, the number of unpaired electrons in Vanadium (V) is three.

3. The electronic configuration of Ti which have atomic number 22 is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{2} {3d}^{2}$

Here, the number of unpaired electrons in Titanium (Ti) is two.

4. The electronic configuration of Cr which have atomic number 24 is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{1} {3d}^{5}$

Here, the number of unpaired electrons in Chromium (Cr) is six (HIGHEST)

5. The electronic configuration of Manganese having atomic number 25 is:

${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {4s}^{2} {3d}^{5}$

Here, the number of unpaired electrons in Manganese (Mn) is five.

Therefore, Chromium (Cr) has the greatest number of unpaired electrons, that is, six.

Learn More:

How many unpaired electrons are present in the ground state of Fe³⁺ (z=26), Mn²⁺ (z=25) and argon (z=18)?

https://brainly.in/question/4097654

The unpaired electrons in Al and Si are present in 3p orbital. Which electrons will experience more effective nuclear charge?

https://brainly.in/question/1983918

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