Question

which of the following best describes the image formed by a convex mirror when the object distance from the mirror is less than the absolute value of the focal length 1) virtual upward and enlarged 2) real inverted and reduced 3)virtual upright and reduced 4) real inverted and enlarged​

Answer 1

Answer:

3virtual upright and reduced

Answer 2

The image formed by the convex mirror will be : (3) virtual, upright and reduced

Suppose, the focal length of a convex mirror (f) = 40 cm

                 the object distance from the pole of the mirror (u) = 20 cm

∵ Given, the object distance from the mirror is less than the absolute value of the focal length.

Let, the distance of the image from the pole of the mirror = v

Applying the formula of mirror,i.e.,

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ , we get,

$\frac{1}{v} + \frac{1}{-20}= \frac{1}{40}$ [ Putting the values with proper sign]

⇒ v = + 40/3 = + 13.33 cm

So, the image is virtual (as + sign is obtained) and upright (by the ray diagram we can get it)

The amount of magnification = |v/u| = height of image/height of object

                                                =|13.33/20| <1

So, height of image/height of object <1

It means, height of image < height of object

So, the image is reduced.