Which of the following bodies has more kinetic energy and by how much if- Body A having mass 1.5kg moving with velocity 30ms-1 or body B having mass 2kg moving with velocity 20ms-1 .
Answers
Answer:
Kinetic energy of A is more than of Kinetic of B
(K.E) A = 1/2 Mv^2
=1/2x1.5x (30)^2
= 675J
(K.E) B =1/2Mv^2
1/2x2x(20)^2
= 400J
Explanation:
I hope it will help you!
Answer:
Body A will have more kinetic energy.
Explanation:
The kinetic energy of a body depends on its mass and velocity. The equation of kinetic energy is:
K = (mv²) / 2
From the equation, it is clear that the effect of velocity will be squared in the final result. Here the body A has greater velocity than body B. But the mass of body A is less than that of B. So we may calculate the kinetic energies separately.
The kinetic energy of body A
K.E = (mv²) / 2
= (1.5 × 30²) / 2
K.E = 675 J
The kinetic energy of body B
K.E = (mv²) / 2
= (2 × 20²) / 2
K.E = 400 J
So kinetic energy of body A is greater than body B