Math, asked by cherylttim, 8 months ago

Which of the following can be a perfect square? (i) A number ending in 3 or 7 (ii) A number ending with odd number of zeros (iii) A number ending with even number of zeros (iv) A number ending in 2

Answers

Answered by arnavgodofmischief
2

iii) option is correct

Answered by gladysgunalan7
6

Answer:

(iii) A number ending with even number of zeroes

Step-by-step explanation:

Let's the see the ending numbers of perfect squares:

1,4,9,16,25,36,49,64,81,....

SO, the ending digits are 1,4,5,6,9

In the case (i) and (iv):

From the above digits we can see that there are no perfect squares with 3,7 or 2 as ending digits

In the case (ii):

A perfect square always has even number of ending zeroes..

eg. 10^2=100; 100^2=10,000; 1000^2=10,00,000

So, the answer is (iii)

Hope you understand my answer.....

Kindly mark me as the brainliest....

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