Which of the following can be a perfect square? (i) A number ending in 3 or 7 (ii) A number ending with odd number of zeros (iii) A number ending with even number of zeros (iv) A number ending in 2
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Answered by
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iii) option is correct
Answered by
6
Answer:
(iii) A number ending with even number of zeroes
Step-by-step explanation:
Let's the see the ending numbers of perfect squares:
1,4,9,16,25,36,49,64,81,....
SO, the ending digits are 1,4,5,6,9
In the case (i) and (iv):
From the above digits we can see that there are no perfect squares with 3,7 or 2 as ending digits
In the case (ii):
A perfect square always has even number of ending zeroes..
eg. 10^2=100; 100^2=10,000; 1000^2=10,00,000
So, the answer is (iii)
Hope you understand my answer.....
Kindly mark me as the brainliest....
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