Question

which of the following can be a Pythagorean triplets?:

a) 2cm 2cm ,4cm b) 5cm, 12cm ,13cm c) 3cm ,5cm ,6cm d) 7cm, 4cm 5 cm. ​

Answer 1

Answer:

Answer :-

As we know that

Pythagoras triplet

1) a² + b² = c²

Let

$\sf \: {2}^{2} + {2}^{2} = {4}^{2}$

$\sf \: 4 + 4 = 16$

8 ≠ 16

Hence, A can't be Pythagoras triplet

2) a² + b² = c²

$\sf \:5 {}^{2} + {12}^{2} = {13}^{2}$

$\sf \: 25 + 144 = 169$

$\sf \: 169 = 169$

Therefore, B can be Pythagoras triplet

3)a² + b² = c²

$\sf {3}^{2} + {5}^{2} = {6}^{2}$

$\sf 9 + 25 = 36$

34 ≠ 36

Hence, C can't be Pythagoras triplet

4) a² + b² = c²

$\sf {5}^{2} + {4}^{2} = {7}^{2}$

$\sf \: 25 + 16 = 49$

41 ≠ 49

Hence, D can't be Pythagoras triplet

Therefore :-

Only B can be Pythagoras triplet.