Math, asked by Siddhartha36, 9 months ago

Which of the following can be a root of 9x5 +ax +b=0,
where a and b are integers
(1) -9
(2) – 5
(3) 1 / 2
(4) 1 / 2​

Answers

Answered by Anonymous
8

Step-by-step explanation:

(3-2x)(3+2x) please solve itSimplify 4x³-2x²+5x-1+8x+x²-6x²+7-6x³+7-6x+3-3x²-x³===> 2x²+5x-1+8x+x²+7-6x+3-3x²

Solution

=2x²+5x-1+8x+x²+7-6x+3-3x²

=2x²+x²-3x²+5x-6x+8x-1+3+7

====>7x+9=0

7x=-9

x=-9/7

x=-1.285

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