Question

Which of the following can bring about free radical chlorination of propane?
(multiple choice)​

Answer 1

A) $SOCL_{2}$

• Why is chloropropane the main byproduct of the monochlorination of propane? As far as I'm aware, 2-chloropropane is intended to generate utilising the free radical method since a secondary free radical is more stable than a primary free radical. Halogenation of alkanes bigger than ethane produces isomeric compounds. As a result, 1-chloropropane and 2-chloropropane are produced as mono-chlorinated compounds when propane is chlorinated. There are five constitutional isomers for trichlorinated propanes, and four constitutionally isomeric dichlorinated products are conceivable.
• Propane's halogenation reveals an intriguing aspect of these processes. A complex alkane does not have equally reactive hydrogens throughout. For instance, there are eight hydrogen atoms in propane, six of which are physically equivalent primary hydrogens and two of which are secondary. Halogenation should result in a 3:1 ratio of 1-halopropane to 2-halopropane mono-halogenated products, representing the primary/secondary numbers, if all of these hydrogen atoms were equally reactive.
• A hydrogen atom may be abstracted by a chlorine radical during the free radical chlorination reaction from either the methylene or one of the methyl groups in propane.

Hence, option A is correct.

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