Question

Which of the following combination of volumes (ml) of C2H4 gas and O2 gas respectively is required to obtain 400ml of CO2 gas ? All the volumes are measuredat STP
a.100,300
b.200,600
c.200,200
d.300,300
Pls with solution

Answer 1

answer is b...........................

Answer 2

Answer: The correct option is b.

Explanation: Reaction of $C_2H_4$ gas and $O_2$ gas is:

$C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$

By stoichiometry,

1 mole of $C_2H_4$ reacts with 3 moles of $O_2$ to produce 2 moles of $CO_2$

Volume of $C_2H_4,O_2\text{ and }CO_2$ are in the ratio 1 : 3 : 2

Volume obtained for 2 moles of $CO_2$ = 400mL

So, Volume obtained for 1 mole of $CO_2$ will be 200mL

According to the Volume ratio

Volume for $O_2=3\times 200=600mL$

Volume of $C_2H_4=1\times 200=200mL$

Hence, the correct option is b.