Question

Which of the following combination/s are not possible?
(1) n = 2, l= 2, m = 0, s = +1/2
(2)n = 3, l = 2, m = -1, s = -1/2
(3) n = 5, I = 3, m = +2, s = 0​

Answer 1

For n= 2

only 2 s exist , 2p and 2 d doesn't exist

For n= 3

only 3 s , 3 p , 3 d exists

For n= 4

only 4 s , 4 p , 4 d , 4f exists

For n=5

only 5s , 5p , 5d , 5f ,5g exists

values of l for orbital s p d f g

s -. 0

p - 1

d - 2

f - 3

g - 4

If value of l is 2 then the value of m can be anything between -2 and +2

spin can be +1/2 , - 1/2 or 0

(1)

hence the answer is a as 2d (l=2)orbital doesn't

exist

(2)n = 3, l = 2, m = -1, s = -1/2

n=3 l=2 (d)

m value varies between +2 and -2 so value of m can be -1

(3)n = 5

I = 3(f) 5f exists

m = +2

m value varies between +3and -3 so value of m can be -2

s = 0