Question

Which of the following combinations of the three resistors 4 Ω, 6 Ω, and 12 Ω will give an equivalent of 2 Ω? (Show working). A. all three resistors in series B. a parallel combination of the 4 Ω and the 6 Ω resistor, in series with the 12 Ω resistor C. All three resistors in parallel D. a series combination of the 6 Ω and 4 Ω resistor with the 12 Ω resistors in parallel​

Answer 1

Answer:

A=R=4+6+12=22ome

B=1/R=1/4+1/6+12=149/12

=R=12/149ome

C=1R=1/4+1/6+1/12=6/12=1/2

C=R=2ome

D=1/R=6+4+1/12=10+1/12=121/120

D=R=120/121ome