Question

Which of the following complexes show easy oxidation?
Ya) (nº-CsHs) Fe
(b) (n-C5H5).Co
(c)(n-C5Hz),Co
(d) (n-CsHs).Ru​

Answer 1

A

because fe gets oxidized very easily.

Answer 2

Answer:

Correct option is (b)  $(n^{5} -C_{5}H _{5}) _{2} Co$ .

Concept:

What is VEC?

It is abbreviated as values of electron concentration. The arrangement of atoms and the chemical bonds that hold them together make up a molecule's chemical structure. There are 14 bonds in all in the VEC molecule.

Find:

We have to find complexes which show easy oxidation.

Solution:

We will find VEC(Values of Electron Concentration) in each options.

a) $(n^{5}-C_{5} H_{5} )_{2} Fe$ = Here the values of electron concentration is $8+5+5=18$.

b)$(n^{5} -C_{5}H _{5}) _{2} Co$ = Values of electron concentration = $9+5+5=19$.

Here we can observe that it has one extra electron and loss of electron takes easily. So we can say that these option have easily oxidation.

c)$(n^{5} -C_{5} H_{5}) _2}Co^{+} }$ = Here, values of electron concentration = $9+5+5-1=18$.

d)$(n^{5} -C_{5} H_{5})_{2}Ru$ = Again, values of electron concentration = $8+5+5=18$.

So, from all these options we can say that option (b) $(n^{5} -C_{5}H _{5}) _{2} Co$ can easily takes oxidation.

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