Question

Which of the following compound has two lone pairs on central element?


CH4



SF4



ICl3



SF6

Answer 1

answer is a

ch4 is the right answer

Answer 2

Compound having two lone pairs on central atom

Explanation:

• First compound is CH₄, as central atom carbon is tetravalent which is bonded with four hydrogen atoms. Therefore, there is no lone pairs on carbon atom in compound CH₄. Hybridization is sp³ and shape is tetrahedral.
• Second compound is SF₄, central atom is Sulphur which has 6 electrons in outermost shell. Out of 6, 4 electrons are bonded covalently with 4 fluorine atoms. So, there is one lone pair in compound SF₄. Hybridization is sp³d and shape is see-saw.
• Third compound is ICl₃, Iodine is the central atom which has 7 electrons in valence shell electron and 3 electrons are bonded with 3 chlorine atoms with 2 lone pairs on iodine atom. Hybridization of this compound is sp³d and shape is T- shape.
• Fourth compound is SF₆, Sulphur is the central atom which has 6 electrons in valence shell electrons and all the electrons are covalently bonded with 6 fluorine atom. Therefore, there is no lone pairs on central atom. Hybridization is sp³d² and shape is octahedral.

So, Option(c) is correct i.e. ICl₃ has two lone pairs.