Which of the following compound(s) has /have percentage of carbon same as that in ethylene (C2H4)
(a) propene
(b) ethyne
(c) benzene
(d) ethane
Answers
Answered by
45
Answer ⇒ Option (a) is correct. Propene.
Solutions ⇒
Molar mass of the Ethylene = 12 × 2 + 1 × 4
= 24 + 4
= 28 g/mole.
Mass of the Carbon Present in Ethylene = 12 × 2
= 24
∴ % composition of the Carbon = 24/28 × 100
= 85.71 %
(a) Molar mass of the Propene(C₃H₆) = 12 × 3 + 1 × 6
= 36 + 6
= 42 g/mole.
Mass of the Carbon present in the Propene = 36 g.
∴ % composition of C = 36/42 ×100
= 85.71 %
(b) Molar mass of the Ethyne (C₂H₂) = 12 × 2 + 1 × 2
= 24 + 2
= 26 g.
Mass of the Carbon Present in Ethyne = 12 × 2
= 24 g.
% compo. of C = 24/26 × 100
= 92.31 %
(c). Molar mass of the Benzene (C₆H₆) = 12 × 6 + 1 × 6
= 72 + 6
= 78 g.
Mass of the C present in Benzene = 12 × 6
= 72 g
% comp. = 72/78 × 100
= 92.31 %
(d). Molecular Mass of the Ethane (C₂H₆) = 12 × 2 + 1 × 6
= 24 + 6
= 30 g
Mass of the C present in Ethane = 12 × 2
= 24 g.
% comp. of the C = 24/30 × 100
= 80 %
From these Calculations we can see that the % composition of the C of the Ethylene is same as that of the Propene.
Hence Propene is correct.
Hope it helps.
Solutions ⇒
Molar mass of the Ethylene = 12 × 2 + 1 × 4
= 24 + 4
= 28 g/mole.
Mass of the Carbon Present in Ethylene = 12 × 2
= 24
∴ % composition of the Carbon = 24/28 × 100
= 85.71 %
(a) Molar mass of the Propene(C₃H₆) = 12 × 3 + 1 × 6
= 36 + 6
= 42 g/mole.
Mass of the Carbon present in the Propene = 36 g.
∴ % composition of C = 36/42 ×100
= 85.71 %
(b) Molar mass of the Ethyne (C₂H₂) = 12 × 2 + 1 × 2
= 24 + 2
= 26 g.
Mass of the Carbon Present in Ethyne = 12 × 2
= 24 g.
% compo. of C = 24/26 × 100
= 92.31 %
(c). Molar mass of the Benzene (C₆H₆) = 12 × 6 + 1 × 6
= 72 + 6
= 78 g.
Mass of the C present in Benzene = 12 × 6
= 72 g
% comp. = 72/78 × 100
= 92.31 %
(d). Molecular Mass of the Ethane (C₂H₆) = 12 × 2 + 1 × 6
= 24 + 6
= 30 g
Mass of the C present in Ethane = 12 × 2
= 24 g.
% comp. of the C = 24/30 × 100
= 80 %
From these Calculations we can see that the % composition of the C of the Ethylene is same as that of the Propene.
Hence Propene is correct.
Hope it helps.
Answered by
14
The correct answer is propene
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