Which of the following compounds are optically inactive
(A)(cH3)2 CHCH2OH
(B)CH3CH2OH
(C)CCL2F2
(D)CH3CHOHC2H5
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Answer:
A⇒ Inactive due to two repetitive units of CH
B⇒ Active due to 4 different units.
C⇒ Active due to 4 different units.
D⇒ Active due to 4 different units.
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