Question

which of the following compounds can not demonstrate the law of multiple proportions
a. NO, NO2. b. CO, CO2 c. H2O, H2O2 d. Na2S, NaF
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Answer 1

answer : option (d)

explanation : according to law of multiple proportions, when two elements combine to form more than one compound, the mass of one element, which combines with a fixed mass of the other element, will always be in simple ratio.

for example, if C and O combine two form CO and CO2,

here in CO , 12g of C ⇔16 g of O

or, 1g of C ⇔ 1.33g of O

in CO2, 12g of C ⇔ 32g of O

or, 1g of C ⇔ 2.66 of O

it is clear that 1.33 : 2.66 = 1 : 2 is in simple ratio so, CO and CO2 follows law of multiple proportions.

from above explanation, all the first three options follow the law but last option , (d) Na2S , NaF doesn't follow. because here three elements are given Na, S and F . but law of multiple proportions is valid for two elements.

Answer 2

Answer:

D) Na2S , NaF