Which of the following compounds contains the maximum number of atoms per molecule
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Answer:
No.of atoms=
Molecular Weight
Weight×atomicity
×N
A
Using the above formula:
a) In 18gm of H
2
O:
No. of atoms=
18
18×3
×N
A
=3N
A
b) In 18gm of O
2
:
No of atoms=
32
18×2
×N
A
=1.12N
A
c) In 18gm of CO
2
:
No. of atoms=
44
18×3
×N
A
=1.23N
A
d) In 18gm of CH
4
:
No. of atoms=
16
18×5
×N
A
=5.63N
A
Therefore, 18gm CH
4
has a maximum number of atoms.
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18gm of CH4
...................
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