Question

Which of the following compounds contains the maximum number of atoms per molecule

Answer 1

Answer:

No.of atoms=

Molecular Weight

Weight×atomicity

×N

A

Using the above formula:

a) In 18gm of H

2

O:

No. of atoms=

18

18×3

×N

A

=3N

A

b) In 18gm of O

2

:

No of atoms=

32

18×2

×N

A

=1.12N

A

c) In 18gm of CO

2

:

No. of atoms=

44

18×3

×N

A

=1.23N

A

d) In 18gm of CH

4

:

No. of atoms=

16

18×5

×N

A

=5.63N

A

Therefore, 18gm CH

4

has a maximum number of atoms.

Answer 2

18gm of CH4

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