Question

which of the following compounds forms a white precipitate with ammonical silver nitrate?
(a) CH3 CH2C = CCH2 (b) CH2 = CHCH2CH3 (c) CH3CH2C=CH (d) CH3CH = CHCH3​

Answer 1

option c will form a white precipitate if instead of double bond there is a triple bond. This is because it forms a terminal alkyne.

And I think it will definitely have a triple bond so as to satisfy the four valencies of carbon....