Question

Which of the following compounds will exhibit

geometrical isomerism?

(A) 1–Phenyl–2–butane

(B) 3–Phenyl–1–butene

(C) 2–Phenyl–1–butene

(D) 1,1–Diphenyl–1–propene​

Answer 1

Option 4 is correct due to restricted rotation i.e double bond and their is presence of different molecules attached to  double bond which satisfy the geometrical isomers condition

.

Answer 2

Hey Dear !

=) (D) 1,1–Diphenyl–1–propene .

Hope , It Helps .