Which of the following contain 9×{10}^{23} oxygen atoms?
1)0.25 moles of glucose
2)0.5 moles of ethyl alcohol
3)1.0 mole of dimethyl ether
4)0.01 moles of sucrose
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Answers
❤HOLA MATE❤
✍️ANSWER:-
✍️Solve by converting the oxygen in each compound into the number of O moles.
✍️Begin by dividing 9x10(23) by Avogadros number to get 1.5 moles of oxygen needed in the correct compound.
✍️Al2O3 has 0.25 x 3 = 0.75 moles of O; SO2 has 2x0.75 =1.5 moles of O; H2O has 1x3=3 moles of O.
So the answer is SO2
❤HOPE IT HELPS❤
Answer:
HEY MATE HERE IS YOUR ANSWER
Explanation:
But of course we must specify the item. In the first scenario we gots
0.25
⋅
m
o
l
aluminium oxide
, i.e.
A
l
2
O
3
..approx.
4.5
×
10
23
⋅
oxygen atoms
...
And in the second scenario we gots
6.022
×
10
23
⋅
m
o
l
−
1
×
2
×
0.75
⋅
m
o
l
oxygen atoms
=
9.0
×
10
23
⋅
oxygen atoms
. So it looks like scenario 2 is the winner. And scenario 3 and 4 contain too many oxygen atoms to fulfil your given criterion.