Question

which of the following contain maximum number of oxygen atom. A) carbon dioxide B) Nitric acid C) Borax D) Potassium permanganate​

Answer 1

Number of atoms in 10g of O atoms =6.023×10

23

So, Number of atoms in 1 g of O atom =

16

6.023×10

23

=0.376×10

23

atoms.

Molecular mass of O

2

=32g

Number of atoms in 32 g of O

2

=2×6.023×10

23

So, number of atoms in 1 g of O

2

=

32

2×6.023×10

23

×1=0.376×10

23

atoms.

The molecular mass of O

2

=48g

Number of atoms in 48gof O

2

=3×6.023×10

23

So, number of atoms n 1g of O

3

=

48

3×6.023×10

23

×1

=0.376×10

23

atoms.

Hence All have the same numbers of atoms.

Answer 2

Answer:

Borax=Na2[B4O5(OH)4].8H2O