Question

Which of the following contains greatest number of oxygen atom 1 g ofO 1 g of O2

Answer 1

Moles of O = m / M

= 1 / 16 = 0.0625 moles

No. of O atom in 1mole = 6.022 × 10^23

So in 0.0625moles = 6.022 × 10^23 × 0.0625

1 g O contain 3.763 × 10^22 atoms

Similarly,

Moles of O2 = 1/32

= 0.0312 moles

So in 0.0312moles = 6.022 × 10^23 × 0.0312

1 g O2 contain 1.87× 10^22 atoms

So 1g of O contains greatest oxygen atoms.


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