Question

Which of the following contains highest number of molecules?
1. 44g of CO2. 2. 36g of H2O
3. 48g of O3. 4. 32g of SO4​

Answer 1

Answer:

36 g of H₂O

Explanation:

Answer 2

Answer: 2. 36g of $H_2O$

Explanation:

1. According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

1) 44 g of $CO_2$

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{44g}{44g/mol}=1moles$

1 mole of $CO_2$ molecule contains =$6.023\times 10^{23}$ of molecules

2) 36 g of $H_2O$

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{36g}{18g/mol}=2moles$

1 mole of $H_2O$ molecule contains =$6.023\times 10^{23}$ of molecules

2mole of $H_2O$ molecule contains =$\frac{6.023\times 10^{23}}{1}\times 2=12.04\times 10^{23}$ of molecules

3) 48 g of $O_3$

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{48g}{48g/mol}=1moles$

1 mole of $O_3$ molecule contains =$6.023\times 10^{23}$ of molecules

4) 32 g of $SO_4$

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{32g}{96g/mol}=0.33moles$

1 mole of $SO_4$ molecule contains =$6.023\times 10^{23}$ of molecules

0.33 moles of $SO_4$ molecule contains =$\frac{6.023\times 10^{23}}{1}\times 0.33=2.0\times 10^{23}$ of molecules