Question

which of the following contains max.no. of molecules
1.36g water
2.28g carbon monoxide

Answer 1

Hi friend,

1) Number of Molecule present in 36 g of water:-

=36 / 18 × N A = 2 N A.

2) Number of Molecule presents in 28g of Carbon monoxide;-

= 28 / 28 × N A = N A

Here, N A is a Avogadro's Number. so 36g of water contains ( 2 N A ) Number of Molecules...i hope it helps.

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