Question

which of the following contains maximum number of oxygen atoms?
1. 1g of O
2. 1g of O2
3. 1g of O3
4. all have sam no. atom​

Answer 1

Answer:

1gm of 03

Explanation:

as moles here will be 1/16

no of atoms will be 1/16 × Na ×3 so....

Answer 2

Explanation:

1. Atomic mass of O atom = 16g

No. of atoms in 16g of O atoms = 6.023×10²³

So,

No. of atoms in 1 g of O atom = 6.023×10²³/16

= 0.376×10²³ atoms

2. Molecular mass of O2 = 32g

No. of atoms in 32 g of O2 = 2×6.023×10²³

So,

No. of atoms in 1 g of O2 = 2×6.023×10²³/32

= 0.376×10²³ atoms.

3. Molecular mass of O3 = 48g

No. of atoms in 48g of O3 = 3×6.023×10²³

So,

No. of atoms in 1g of O3 = 3×6.023×10²³/48

= 0.376×10²³ atoms.

Hence, All have the same numbers of atoms.

- the correct option is D

Thank U ☺️

@inspirebkb