Question

Which of the following contains the greatest number of atoms?

(1) 1g of butane

(2) 1g of N2

(3) 1g of Ag

(4) 1g of water​

Answer 1

Answer:

4) 1 g of water

Explanation:

Coz, masses are 58,28,108 and 18

The least is 18

Therefore,

Atoms = Given mass/molecular mass * 6.022 *10^23

1/18 * NA is the highest no. of atoms......

Answer 2

Answer:

1 g of butane

Explanation:

$1gm \: of \: butane \: = 1 \div 58 \times 14 \: \times 6.023 \times {10}^{23} atoms \\ 1gm \: nitrogen = 1 \div 28 \times 2 \times 6.023 \times {10}^{23} atoms \\ 1gm \: silver = 1 \div 108 \times 6.023 \times {10}^{23} atoms \\ 1gm \: water = 1 \div 18 \times 3 \times 6.023 \times {10}^{23} atoms$