Question

which of the following electronic configuration would you expect to have the lowest ionisastion enthalpy? explainA...1s2 2s2 2p6 B......1s2 2s2 2p5....C....1s2 2s2 2p6 3s1

Answer 1

Explanation:

When considering ground-state electronic configurations of atoms, the electrons must fill the lowest energy shells first. It is known as the Aufbau...

Answer 2

Explanation:

HEY MATE

HERE IS YOUR ANSWER

ACCORDING TO QUESTION

OPTION C IS CORRECT

OPTIONA(Ne)- the e. c. contain completely filled 2p orbital so to remove electroN from it we require a larger amount of energy

SO HAS MAXIMUM I. P.

OPTION B - THE E.C. GIVEN CONTAIN REQUIRE 1 MORE ELECTION TO COMPLETE IT'S OCTATE SO TO REMOVE AN ELECTRON WE REQUIRE A LARGE AMOUNT OF ENERGY

SO HAS LARGER IP

option C(Na)- THE E. C. CONTAIN AN ELECTION in it's outer most shell and it can easily donate that election to become fully filled 2p orbital

hence have least I.P.

IP1>IP2>IP3

HOW IT WILL HELP YOU

THANKING YOU