Question

which of the following electrons configuration is correct for nickel (atomic number 28)​

Answer 1

Answer:

2-8-16-2.

Explanation:

Located in the fourth period on the table of elements, nickel is a transition metal sandwiched between cobalt and copper. As each element adds an electron to one of the orbits, nickel adds its additional electron to the third orbital. It creates the electron configuration of 2-8-16-2.

Ni electronic configuration: [Ar], 3d8, 4s2

Atomic Number of Nickel (Ni) = 28

Electronic configuration is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d8

or [Ar], 3d8, 4s2

where [Ar] is Argon with atomic number 18

Answer 2

To find:

Correct electronic configuration for nickel with atomic number 28.

Solution:

Atomic number of 28 signifies the fact that the total number of electrons in a nickel atom is 28.

So, the electronic configuration can be written as:

$\boxed{ \sf{(Ni)_{28} = 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3{p}^{6} 4 {s}^{2} 3{d}^{8} }}$

So, electrons in different shells:

K shell : 2 electrons

L shell : 8 electrons

M shell : 16 electrons

N shell : 2 electrons

This electronic configuration can also be written in terms of of noble gas Argon which has a atomic number of 18.

$\boxed{ \sf{(Ni)_{28} = [Ar] 4 {s}^{2} 3{d}^{8} }}$

Hope It Helps.