Question

Which of the following elements are correctly arranged with respect to their second ionization energy? (a) O>N (b) B>C (c) Cu > Zn (d) C> Si ​

Answer 1

Answer:

(c) Cu > Zn

Explanation:

(c) Cu > Zn

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Answer 2

Explanation:

O > F > N > C

Consider the configurations of the given elements after the loss of an electron.

C

+

: 1s

2

2s

2

2p

1

N

+

: 1s

2

2s

2

2p

2

O

+

: 1s

2

2s

2

2p

3

F

+

: 1s

2

2s

2

2p

4

We notice that O has a half-filled orbital and hence has the highest I.E. among these. Also, carbon can lose an electron easily. Fluorine will reach a half-filled configuration upon the loss of an electron. Hence, the order is O>F>