Question

which of the following equation do we have x=3 as a solution

x+4=7
x-3=1
2x+5=2
x+3=7​

Answer 1

$1) \: x + 4 = 7$

$3 + 4 = 7$

$7 = 7$

$2) \: x - 3 = 1$

$3 - 3 = 1$

$0≠1$

$3)2x + 5 = 2$

$2(3) + 5 = 2$

$6 + 5 = 2$

$11≠2$

$4) \: x + 3 = 7$

$3 + 3 = 7$

$6≠7$

$x + 4 = 7 \: is \: a \: solution$