Which of the following equation has the same root of -5?
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Answer:
⇒ The given quadratic equation is (k+1)x
2
+2(k+3)x+(k+8)=0, comparing it with ax
2
+bx+c=0.
⇒ We get, a=(k+1),b=2(k+3) and c=k+8
⇒ The roots are real and equal.
∴ b
2
−4ac=0
⇒ (2(k+3))
2
−4(k+1)(k+8)=0
⇒ 4(k
2
+6k+9)−4(k
2
+8k+k+8)=0
⇒ 4k
2
+24k+36−4k
2
−36k−32=0
⇒ −12k+4=0
⇒ 12k=4
⇒ k=
12
4
⇒ k=
3
1
∴ The given statement is true.
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