Question

Which of the following equations correctly represents the
standard heat of formation (∆ f H°) of methane ?
(a) C (diamond) + 4H(g) → CH₄(g)
(b) C (diamond) + 2H₂ (g) → CH₄(g)
(c) C (graphite) + 2H₂ (g) → CH₄(g)
(d) C (graphite) + 4H(g) → CH₄(g)

Answer 1

Answer:

B and C

Explanation:

because a atom of hydrogen is never alone it is always in form of molecules

Answer 2

The correct representation of  the  standard heat of formation (∆ f H°) of methane is as follows.

$\bold{C_{(graphite)}+2H_{2}\rightarrow CH_{4}(g)}$

Step by step explanation:

Standard heat for the formation of a compound is the change in enthalpy from its constituent elements during the formation of 1 mole of the substance.

The equilibrium reaction of the formation of the methane reaction consists the equal amount of reactants and products are same at the both side of the reactions.

Therefore, the  The correct representation of  the  standard heat of formation (∆ f H°) of methane is as follows.

$\bold{C_{(graphite)}+2H_{2}\rightarrow CH_{4}(g)}$

Hence correct option is "c".

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