Question

Which of the following equations
does not have real roots?
x² + 4x +4=0
x² + 9x +16= 0
x² + x +1 = 0
x² + 3x +1=0​

Answer 1

Answer:

formula for finding real or unreal root#=b²-4ac

Step-by-step explanation:

hence here in 1st equation a = 1,b=4,c=4

b²-4ac=(4)²-4(1)(4)

=16-16=0

hence it has real and equal root

in 2nd equation

a=1,b=9,c=16

b²-4ac=(9)²-4(1)(16)

81-64=17

hence it has real and unequal root

in 3rd equation

a=1,b=1,c=1

b²-4ac=(1)²-4(1)(1)

1-4=-3

hence as the number is negative it has unreal roots

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