which of the following equations has no real roots?
1.x^2 + 2x - 7,
2. 3x^2 - 7x + 4,
3. 2x^2 - 3x - 4,
4.4x^2 - 3x +5
Answers
Answer:
x^2+2x-7 is having no real roots
Step-by-step explanation:
given,
given, 1) =x^2+2x-7
given, 1) =x^2+2x-7 =b^2-4ac
given, 1) =x^2+2x-7 =b^2-4ac =4-28
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots 4)=4x^2-3x+5
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots 4)=4x^2-3x+5 =b^2-4ac
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots 4)=4x^2-3x+5 =b^2-4ac =9-80
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots 4)=4x^2-3x+5 =b^2-4ac =9-80 =71
given, 1) =x^2+2x-7 =b^2-4ac =4-28 =-24therefore, it has no real roots 2)=3x^2-7x+4 =b^2-4ac =49-48 =1therefore, it has real and distinct roots 3)=2x^2-3x-4 =b^2-4ac =9+32 =41therefore, it has real and distinct roots 4)=4x^2-3x+5 =b^2-4ac =9-80 =71therefore, it has real and distinct roots
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