Question

Which of the following equations have a solution of n = 2 1/4 ? Select all that apply.

4n = 9
n ÷1/2 = 1/8
2n + 3 = 7 1/2
n - 2 1/4 = 0
2 1/4n = 0

Answer 1

Find the equations that has a solution of $n=2\frac{1}{4}$

Definition:

The solution of an equation is the set of all values that,when substituted for unknowns , make an equation true.

Step-by-step explanation:

The given solution can be rewritten as,

[tex]n=2\frac{1}{4}\\ n=\frac{9}{4} [/tex]

Case1:

[tex]4n=9\\ n=\frac{9}{4} [/tex]

It satisfies the given solutions.

Case2:

[tex]n/\frac{1}{2}=\frac{1}{8} \\ n=\frac{1}{8} *\frac{1}{2} \\ n=\frac{1}{16} [/tex]

It does not satisfies the given solutions.

Case3:

[tex]2n+3=7\frac{1}{2} \\ 2n+3=\frac{15}{2} \\ 2n=\frac{15}{2}-3\\ 2n=\frac{9}{2}\\ n=\frac{9}{4} [/tex]

It satisfies the given solutions.

Case4:

[tex]n-2\frac{1}{4}=0\\ n-\frac{9}{4}=0\\ n=\frac{9}{4} [/tex]

It satisfies the given solutions.

Case5:

[tex]2\frac{1}{4}n =0\\\\ \frac{9}{4}n=0\\ n=0[/tex]

It does not satisfies the given solutions.

Therefore,the equations $4n=9$,$2n+3=7\frac{1}{2}$ and $n-2\frac{1}{4}=0$ satisfies the given solution $n=2\frac{1}{4}$.