Question

Which of the following expression shows that rational number are asdociative under multiplication 2/3×(-6/7×3/5)=(2/3×_6/7)×3/5
2/3×-(6/7×3/5)=2/3×(3/5×-6/7)
2/3×-(6/7×3/5)=(3/5×2/3)×-6/7
(2/3×-6/7)×3/5=(-6/7×2/3)×3/5

Answer 1

Answer:

-

Step-by-step explanation:

2/3×(-6/7×3/5)=(2/3×-6/7)×3/5

2/3×-(6/7×3/5)=2/3×(3/5×-6/7)

2/3×-(6/7×3/5)=(3/5×2/3)×-6/7

(2/3×-6/7)×3/5=(-6/7×2/3)×3/5

Answer 2

Answer:

$this \: i s \: your \: answer \:$

please mark me brain list