Which of the following expressions are equivalent to -\dfrac{-8}{7}−
7
−8
minus, start fraction, minus, 8, divided by, 7, end fraction?
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Answers
Answer:
12407
Step-by-step explanation:
The given expression is
\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(987+254)−21
We need to find the simplified form of the given expression.
It can be rewritten as
\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}(9+87+2+54)−21
Combine integers and fractions separately.
(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})(9+2)+(87+54−21)
Taking LCM we get
11+\dfrac{35+32-20}{40}11+4035+32−20
11+\dfrac{47}{40}11+4047
In can be written as
11+\dfrac{40+7}{40}11+4040+7
11+1+\dfrac{7}{40}11+1+407
12+\dfrac{7}{40}12+407
12\dfrac{7}{40}12407
Therefore, the expression 12\dfrac{7}{40}12407 is equivalent to the given expression.
12407
Explanation:
The given expression is
\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(987+254)−21
We need to find the simplified form of the given expression.
It can be rewritten as
\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}(9+87+2+54)−21
Combine integers and fractions separately.
(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})(9+2)+(87+54−21)
Taking LCM we get
11+\dfrac{35+32-20}{40}11+4035+32−20
11+\dfrac{47}{40}11+4047
In can be written as
11+\dfrac{40+7}{40}11+4040+7
11+1+\dfrac{7}{40}11+1+407
12+\dfrac{7}{40}12+407
12\dfrac{7}{40}12407
Therefore, the expression 12\dfrac{7}{40}12407 is equivalent to the given expression.
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