Question

which of the following factorisations is incorrect 200y^2 = 2(10y + 1) (10y - 1)

Answer 1

Step-by-step explanation:

200y^2 = 2(10y + 1) (10y - 1)

$200 {y}^{2} = 2(10y + 1)(10y - 1) \\ 200 {y}^{2} = (20y + 2)(10y - 1) \\ 200 {y}^{2} = 200 {y}^{2} - 20y + 20y - 2 \\ 200 {y}^{2} - 200 {y}^{2} = 20y - 20y - 2 \\ 0 = 0 - 2$