Question

Which of the following has a maximum number of atoms? (b) 36 g of O2 (a) 36 g of H20 (d) 36 g of CH4 (c) 36 g of CO2​

Answer 1

Answer:

d) 36g of CH4

Explanation:

No. of moles = Molecular Weight/Molar Mass

$36g \ H_{2}O = \frac{36}{(2 * 1) + 16)}=\frac{36}{18} = 2\ moles$

$36g\ O_{2} = \frac{36}{16*2} = \frac{36}{32} = 1.125\ moles$

$36g\ CO_{2} = \frac{36}{12 + (2*16)} = \frac{36}{44} = 0.81\ moles$

$36g\ CH_{4} = \frac{36}{12+(4*1)} = \frac{36}{16} = 2.25\ moles$

Clearly, 36g of CH4 has more molecules because of more no. of moles.