Question

Which of the following has arranged in order of increasing oxidation numbers of nitrogen?
(1) NH3 < N2 O5
(2) NO2+< NO3â (3) NH4+ < N2H4< NH2OH < N2O
(4) NO2< NaN3< NH4+ < N2O

Answer 1

3          NO3- N2O4 N2O N2 N2H4 NH3

oxidation numbers        . . .       +5 .     . . .+4 . .    +1 . .0   . . .-2   . . .-3

Answer 2

Answer:

We can find the oxidation number of any element in a compound by a method that says put the charge on all atoms that makes them stable. For example +1 for hydrogen and -2 for Oxygen and assign a variable for the atom for which we have to find oxidation state And then equating them with the charge on compound. By this method; we will get the oxidation no. of N in compounds as follows:

NH3= -3, N2O5 = +5, NO2+ = +3, NO3 = +6, NH4+ = -3, N2H4 = -2, NH2OH = -1, N20 = +1, NO2 = +4, NaN3 = -1/3,

By analysing the options, we'll get that Only first option is correct.