Chemistry, asked by rahul80kalindi12, 2 months ago

Which of the following has been arranged in order of deaeasing oxidation
number of sulphur
(a) H2S2O7 > Na2S4O3>Na2S2O3>Ss
(b) FeS2 > S04^2->SO3^2-> HSO4^-
(c) H2SO5 > H2SO3 >SCI2 > H2SO4
(d) H2SO4> SO2> H2S>H2S2O8​

Answers

Answered by hardiksharma50
0

Answer:  user_photo

11th

Chemistry

Redox Reactions

Oxidation Number

Which of the following has/...

Chemistry

Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?

This question has multiple correct options

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Hard

Answer

Correct option is

A

H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

 

C

H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S

Let x be the oxidation state of S.

a.  Oxidation state of S in

    H  

2

​  

S  

2

​  

O  

7

​  

:2+2x−14=0⇒x=6

    Na  

2

​  

S  

4

​  

O  

6

​  

:2+4x−12=0⇒x=2.5

    Na  

2

​  

S  

2

​  

O  

3

​  

:2+2x−6=0⇒x=2

    S  

8

​  

:8x=0⇒x=0

Therefore, the decreasing order is H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

.

c.  H  

2

​  

SO  

5

​  

  (Peroxo linkage)

    Oxidation state of S=+6

    H  

2

​  

SO  

3

​  

:2+x−6=0

    Oxidation state of S=+4

    SCl  

2

​  

:x−2=0

    Oxidation state of S=+2

    H  

2

​  

S:2+x=0

    Oxidation state of S=−2

Therefore, the decreasing order is H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S.user_photo

11th

Chemistry

Redox Reactions

Oxidation Number

Which of the following has/...

Chemistry

Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?

This question has multiple correct options

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Hard

Answer

Correct option is

A

H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

 

C

H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S

Let x be the oxidation state of S.

a.  Oxidation state of S in

    H  

2

​  

S  

2

​  

O  

7

​  

:2+2x−14=0⇒x=6

    Na  

2

​  

S  

4

​  

O  

6

​  

:2+4x−12=0⇒x=2.5

    Na  

2

​  

S  

2

​  

O  

3

​  

:2+2x−6=0⇒x=2

    S  

8

​  

:8x=0⇒x=0

Therefore, the decreasing order is H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

.

c.  H  

2

​  

SO  

5

​  

  (Peroxo linkage)

    Oxidation state of S=+6

    H  

2

​  

SO  

3

​  

:2+x−6=0

    Oxidation state of S=+4

    SCl  

2

​  

:x−2=0

    Oxidation state of S=+2

    H  

2

​  

S:2+x=0

    Oxidation state of S=−2

Therefore, the decreasing order is H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S.user_photo

11th

Chemistry

Redox Reactions

Oxidation Number

Which of the following has/...

Chemistry

Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?

This question has multiple correct options

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Hard

Answer

Correct option is

A

H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

 

C

H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S

Let x be the oxidation state of S.

a.  Oxidation state of S in

    H  

2

​  

S  

2

​  

O  

7

​  

:2+2x−14=0⇒x=6

    Na  

2

​  

S  

4

​  

O  

6

​  

:2+4x−12=0⇒x=2.5

    Na  

2

​  

S  

2

​  

O  

3

​  

:2+2x−6=0⇒x=2

    S  

8

​  

:8x=0⇒x=0

Therefore, the decreasing order is H  

2

​  

S  

2

​  

O  

7

​  

>Na  

2

​  

S  

4

​  

O  

6

​  

>Na  

2

​  

S  

2

​  

O  

3

​  

>S  

8

​  

.

c.  H  

2

​  

SO  

5

​  

  (Peroxo linkage)

    Oxidation state of S=+6

    H  

2

​  

SO  

3

​  

:2+x−6=0

    Oxidation state of S=+4

    SCl  

2

​  

:x−2=0

    Oxidation state of S=+2

    H  

2

​  

S:2+x=0

    Oxidation state of S=−2

Therefore, the decreasing order is H  

2

​  

SO  

5

​  

>H  

2

​  

SO  

3

​  

>SCl  

2

​  

>H  

2

​  

S.

Explanation:

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