Which of the following has been arranged in order of deaeasing oxidation
number of sulphur
(a) H2S2O7 > Na2S4O3>Na2S2O3>Ss
(b) FeS2 > S04^2->SO3^2-> HSO4^-
(c) H2SO5 > H2SO3 >SCI2 > H2SO4
(d) H2SO4> SO2> H2S>H2S2O8
Answers
Answer: user_photo
11th
Chemistry
Redox Reactions
Oxidation Number
Which of the following has/...
Chemistry
Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?
This question has multiple correct options
Hard
Answer
Correct option is
A
H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
C
H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S
Let x be the oxidation state of S.
a. Oxidation state of S in
H
2
S
2
O
7
:2+2x−14=0⇒x=6
Na
2
S
4
O
6
:2+4x−12=0⇒x=2.5
Na
2
S
2
O
3
:2+2x−6=0⇒x=2
S
8
:8x=0⇒x=0
Therefore, the decreasing order is H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
.
c. H
2
SO
5
(Peroxo linkage)
Oxidation state of S=+6
H
2
SO
3
:2+x−6=0
Oxidation state of S=+4
SCl
2
:x−2=0
Oxidation state of S=+2
H
2
S:2+x=0
Oxidation state of S=−2
Therefore, the decreasing order is H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S.user_photo
11th
Chemistry
Redox Reactions
Oxidation Number
Which of the following has/...
Chemistry
Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?
This question has multiple correct options
Hard
Answer
Correct option is
A
H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
C
H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S
Let x be the oxidation state of S.
a. Oxidation state of S in
H
2
S
2
O
7
:2+2x−14=0⇒x=6
Na
2
S
4
O
6
:2+4x−12=0⇒x=2.5
Na
2
S
2
O
3
:2+2x−6=0⇒x=2
S
8
:8x=0⇒x=0
Therefore, the decreasing order is H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
.
c. H
2
SO
5
(Peroxo linkage)
Oxidation state of S=+6
H
2
SO
3
:2+x−6=0
Oxidation state of S=+4
SCl
2
:x−2=0
Oxidation state of S=+2
H
2
S:2+x=0
Oxidation state of S=−2
Therefore, the decreasing order is H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S.user_photo
11th
Chemistry
Redox Reactions
Oxidation Number
Which of the following has/...
Chemistry
Which of the following has/have been arranged in order of decreasing oxidation number of sulphur?
This question has multiple correct options
Hard
Answer
Correct option is
A
H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
C
H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S
Let x be the oxidation state of S.
a. Oxidation state of S in
H
2
S
2
O
7
:2+2x−14=0⇒x=6
Na
2
S
4
O
6
:2+4x−12=0⇒x=2.5
Na
2
S
2
O
3
:2+2x−6=0⇒x=2
S
8
:8x=0⇒x=0
Therefore, the decreasing order is H
2
S
2
O
7
>Na
2
S
4
O
6
>Na
2
S
2
O
3
>S
8
.
c. H
2
SO
5
(Peroxo linkage)
Oxidation state of S=+6
H
2
SO
3
:2+x−6=0
Oxidation state of S=+4
SCl
2
:x−2=0
Oxidation state of S=+2
H
2
S:2+x=0
Oxidation state of S=−2
Therefore, the decreasing order is H
2
SO
5
>H
2
SO
3
>SCl
2
>H
2
S.
Explanation: