Question

which of the following has greatest no. of atoms a)1gram of butane b)1gram of nitrogen c)1gram of silver d)1gram of water

Answer 1

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For butane n = 4, so the formula is C4H10.

No of atoms in a compound =14

we have to convert 1 gram of butane to moles of butane. For that we'll need to know the molar mass of butane, 
 4*12 + 10*1 
 =58 g/mol.

Moles = weight / molecular mass

Moles = 1/58 =0.0172

No. Of molecules = avogadro no * moles 
 = 6.023×10^23 * 0.0172
 = 1.038 × 10^22

Total no of atoms = no of atoms in compound * no of molecules
 = 14 × 1.038 ×10^22
 = 1.453 ×10^23

So there will be 1.453×10^23 atoms in Butane

Answer 2

Answer:

Moles = weight / molecular mass

Moles = 1/58 =0.0172

No. Of molecules = avogadro no * moles 

 = 6.023×10^23 * 0.0172

 = 1.038 × 10^22

Total no of atoms = no of atoms in compound * no of molecules

 = 14 × 1.038 ×10^22

 = 1.453 ×10^23

So there will be 1.453×10^23 atoms in Butane

Explanation: