English, asked by guptasakshi5603, 4 months ago

Which of the following has larger number of molecules?
7g of nitrogen or 1g of hydrogen

Answers

Answered by Mysterioushine
10

\LARGE\underline{\underline{\pink{\bf{Required\:answer:-}}}}

a. 7g of Nitrogen

Step - (1) : Calculate the number of moles of the given substance.

Number of moles of a substance is calculated by ,

 \\   \star \: \boxed{ \sf{ \purple{n = \dfrac{Given\:weight}{Atomic\:weight}}}} \\

Given weight of Nitrogen = 7g

Atomic weight of Nitrogen = 28 amu

 \\ :   \implies \sf \: n_{(moles)} =  \frac{7}{28}  \\  \\

 \\   : \implies \sf \: n_{(moles)} =  \frac{1}{4}  \\  \\

 \\  :  \implies {\boxed{\red{\mathfrak{n_{(moles)} = 0.25 \: mol}}}} \\  \\

Step-(2) : Multiplying the number of moles of the given substance with the Avogadro number.

Avogadro number = 6.023 × 10²³

Number of moles = 0.25 mol

 \\   : \implies \sf \: n_{(molecules)} = 6.023 \times  {10}^{23}  \times 0.25 \\  \\

 \\   : \implies{\boxed{\pink{\mathfrak{n_{(molecules)} =1.505 \times  {10}^{23} }}}}  \: \bigstar \\  \\

Number of molecules in 7g of Nitrogen is 1.505 × 10²³.

b. 1g of Hydrogen

Step - (1) : Calculate the number of moles of the given substance.

Given weight of Hydrogen = 1

Atomic weight of hydrogen = 2 amu

 \\   : \implies \sf \:n_{(moles)}  =  \frac{1}{2}  \\  \\

 \\   : \implies {\boxed{\red{\mathfrak {{n_{(moles)} = 0.5 \: mol}}}}} \\  \\

Step-(2) : Multiplying the number of moles of the given substance with the Avogadro number.

Avogadro number = 6.023 × 10²³

Number of moles = 0.5 mol

 \\   : \implies \sf \: n_{(molecules)} = 6.023 \times  {10}^{23}  \times 0.5 \\  \\

 \\   : \implies{\boxed{\pink{\mathfrak{n_{(molecules)} = 3.0115 \times  {10}^{23} }}}}  \: \bigstar \\  \\

Comparing the number of molecules in 7 grams of Nitrogen and in 1g of Hydrogen .

\longrightarrow 3.0115 × 10²³ > 1.505 × 10²³

\\ \longrightarrow{\sf{n_{(molecules\:in\:H)} > n_{(molecules\:in\:N)}}}

Hence , 1g of Hydrogen contains more molecules than 7g of Nitrogen.

Answered by Theopekaaleader
0

a. 7g of Nitrogen

Step - (1) : Calculate the number of moles of the given substance.

Number of moles of a substance is calculated by ,

n= Atomicweight/Givenweight

Given weight of Nitrogen = 7g

Atomic weight of Nitrogen = 28 amu

:⟹n (moles)

=28/7

:⟹n (moles)

= 4/1

:⟹ n _(moles)

=0.25mol

Step-(2) : Multiplying the number of moles of the given substance with the Avogadro number.

Avogadro number = 6.023 × 10²³

Number of moles = 0.25 mol

:⟹n (molecules)

=6.023×10 ⅔×0.25

:⟹ n (molecules)

=1.505×10 ⅔ ★

Number of molecules in 7g of Nitrogen is 1.505 × 10²³.

b. 1g of Hydrogen

Step - (1) : Calculate the number of moles of the given substance.

Given weight of Hydrogen = 1

Atomic weight of hydrogen = 2 amu

:⟹n (moles)

= 2/1

:⟹ n (moles) =0.5mol

Step-(2) : Multiplying the number of moles of the given substance with the Avogadro number.

Avogadro number = 6.023 × 10²³

Number of moles = 0.5 mol

:⟹n (molecules)

=6.023×10 ⅔ ×0.5

:⟹ n (molecules)

=3.0115×10 ⅔ ★

Comparing the number of molecules in 7 grams of Nitrogen and in 1g of Hydrogen .

⟶ 3.0115 × 10²³ > 1.505 × 10²³

⟶n (moleculesinH)

>n (moleculesinN)

Hence , 1g of Hydrogen contains more molecules than 7g of Nitrogen.

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