Question

Which of the following has largest atom
a ,5g of cu atom

Answer 1

Answer:

Complete step by step solution:

We know, the molar mass of Cu is 63.5g

I.e. 63.5g of copper contains Avogadro’s number (NA) atoms of copper

∴63.5g copper= 6.023×1023atoms of copper.

So, following unitary method, we get-

0.635g of copper=(6.023×1023×0.635)÷63.5atoms of copper= 6.023×1021atoms of copper

Similarly, for 1g of copper we have,

1g of copper= (6.023×1023×1)÷63.5=9.485×1021atoms of copper

For 0.5g atom of Cu,

Number of atoms= 0.5×6.022×1023= 3.011×1023atoms of copper

Now, for 0.25 moles of copper,

∵1 mole of copper= 6.023×1023atoms of copper

∴0.25 moles of copper= 0.25×6.023×1023=1.50575×1023atoms of copper.

From the above calculations it is clear that 0.5g atom of Copper has the highest number of atoms present.