Question

Which of the following has least mass: a) 2g atom of Nitrogen b) 3X10 23 atoms of C c) 1 mole of S d) 7g of Ag

Answer 1

Mass of 7 g of Ag will be the least as it has least number of moles.

Explanation:

Smaller is the number of moles present in an atom smaller will be its mass. Therefore, we will calculate the number of moles of given elements as follows.

             No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

(a)   2 g atom of Nitrogen

           No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

                                 = $\frac{2 g}{14 g/mol}$

                                 = 0.142 mol

(b)  $3 \times 10^{23}$ atoms of C

       No. of moles = $\frac{3 \times 10^{23}}{6.022 \times 10^{23}}$

                             = 0.498 mol

(c)   1 mole of S

As 1 mole of every substance contains $6.022 \times 10^{23}$ atoms. Therefore, 1 mole of sulfur also contains $6.022 \times 10^{23}$ atoms.

(d)  7 g of Ag

              No. of moles = $\frac{\text{mass}}{\text{molar mass}}$

                                 = $\frac{7 g}{107.86 g/mol}$

                                 = 0.064 mol  

Therefore, mass of 7 g of Ag will be the least as it has least number of moles.

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Answer 2

Answer:

Mass of 7 g of Ag will be the least as it has least number of moles.

Explanation:

Mass of 7 g of Ag will be the least as it has least number of moles.

Mass of 7 g of Ag will be the least as it has least number of moles.