Question

which of the following has maximum no. of molecules a) 7g N2 b) 2g H2 3) 8g O2 4) 20g NO2​

Answer 1

Answer:

2 g H2 has maximum number of molecules  

Explanation:

7 g N2 =7 NA /14 (NA =6.022 ×10^23)

 =NA /2

2g H2 =NA

8 g O2=NA/2

20g NO2 =20 NA/46

HOPE IT WILL HELP YOU..............

Answer 2

Answer:

Explanation:

first calculate no. of moles

then multiply by Na