Question

which of the following has maximum number of atoms (a) 18g of water (b) 16g of o2(c) 4.4g of co2 (d) 16g of ch4​

Answer 1

Answer:

option b is correct 16g oxygen

Answer 2

Answer:

Answer: (d) 16g of $ch_{4}$

Explanation:

Answer: (d) 16g of $ch_{4}$

Number of atoms = Mass of substance × Number of atoms in the molecule/ Molar mass × NA

NA = 6.023×1023

(a) 18g of $h_{2} o$

⇒ 18 x 3/18 × NA

= 3 NA

(b) 16 g of $o_{2}$

⇒ 16 x 2 /32 × NA

= 1 NA

(c) 4.4 g of$co_{2}$

= 4.4 x 3/44 × NA

= 0.3 NA

(d) 16 g of$ch_{4}$

= 16 x 5 /16 × NA

= 5 NA

hence, the maximum number of atoms are in 16g of $ch_{4}$.

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