Question

Which of the following has not real roots? *

3q² + 2q - 1 = 0

2q² + q - 2 = 0

4q² + 3q + 1 = 0

4q² + 4q + 1 = 0​

Answer 1

Answer:

4q² + 3q + 1 = 0

Explanation:

here,

a= 4

b= 3

c= 1

•°• D= b² – 4ac

= 3² – 4×4×1

= 9 – 16

= –5

As D= –5 which is < 0,

this means that the nature of roots are not real roots.

Hope its helps..