Question

which of the following has number of molecules present equal to those present in 16 g of oxygen

a)16g O3
b)32g SO2
c)16g SO2​

Answer 1

Look bro it's easy........

16g Of oxygen means 0.5 moles of oxygen.

So total number of molecules is ( k*0.5) where k is Avogadro number.

Similarly 32g SO2 has 0.5 moles of SO2 ( mass given / molecular weight)

So total molecules in option b is ( k*0.5)

Hence the answer is b

☺☺

Answer 2

Answer:

N moles=given wt÷molecular we

oxygen moles=16/3=½mole

similarly 32g of so2

=32/32+2(16)

=32/64

=½ mole

both are equal