Question

which of the following has one lone pair of electrons ?
3) IF3 b) ICI
c) IF5 a) CIF3​

Answer 1

Explanation:

IF5 have one lone pair

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Answer 2

The correct option is (c) IF5.

• Electron pair = valence electron+bond pair Formula for calculating electron pair =
• $\frac{V+M-C+A}{2}$
• Here, V= number of valence electrons

M= no of monovalent atoms attached.

C= charge on the cation

A= charge on the anion

• So, IF3 electron pair =
• $\frac{7+3}{2}$
• $= 5$

Lone pair of IF3 = 5-3

= 2

Similarly, ICl has electron pair=

$\: \: \: \: \: = \frac{7+1}{2}$

$\: \: \: \: \: \: \: = 4$

Lone pair of ICl = 4-1

= 2

• Electron pair in IF5

$\: \: \: \: \: = \frac{7 + 5}{2}$

$\: \: \: \: \: = 6$

Lone pair of IF5 = 6-5

= 1

• Electron pair in ClF3

$\: \: \: \: = \frac{7 + 3}{2}$

$\: \: \: \: = 5$

Lone pair of IF5 = 5-3

= 2

So, IF5 has one lone pair of electrons.