which of the following has the largest number of atoms
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Answered by
0
Answer:
lithium
Hence, 1g lithium has the largest number of atoms.
Answered by
0
Answer:
ANSWER
(i) 1g Au=
197
1
mol atom of Au
=
197
1
×6.022×10
23
atoms of Au
(ii) 1g Na=
23
1
mol atom of Na
=
23
1
×6.022×10
23
atom of Na
(iii) 1g Li=
7
1
mol atom of Li
=
7
1
×6.022×10
23
atom of Li
(iv) 1g Cl
2
=
71
1
mol molecules of Cl
2
=
71
1
×6.022×10
23
molecules of Cl
2
=
71
2
×6.022×10
23
atoms of Cl
2
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